Base | Representation |
---|---|
bin | 111110001100010000… |
… | …0000110011101110011 |
3 | 110202201200101201112012 |
4 | 1330120200012131303 |
5 | 4142010043220301 |
6 | 141204312153135 |
7 | 12435422142410 |
oct | 1743040063563 |
9 | 422650351465 |
10 | 133555054451 |
11 | 5170538a165 |
12 | 21a733987ab |
13 | c795579050 |
14 | 666d6b9107 |
15 | 3719ee7ebb |
hex | 1f18806773 |
133555054451 has 16 divisors (see below), whose sum is σ = 164385681600. Its totient is φ = 105663356928.
The previous prime is 133555054417. The next prime is 133555054459. The reversal of 133555054451 is 154450555331.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133555054451 is a prime.
It is a super-2 number, since 2×1335550544512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133555054399 and 133555054408.
It is not an unprimeable number, because it can be changed into a prime (133555054459) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1858355 + ... + 1928883.
It is an arithmetic number, because the mean of its divisors is an integer number (10274105100).
Almost surely, 2133555054451 is an apocalyptic number.
133555054451 is a deficient number, since it is larger than the sum of its proper divisors (30830627149).
133555054451 is a wasteful number, since it uses less digits than its factorization.
133555054451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91358.
The product of its (nonzero) digits is 450000, while the sum is 41.
The spelling of 133555054451 in words is "one hundred thirty-three billion, five hundred fifty-five million, fifty-four thousand, four hundred fifty-one".
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