Base | Representation |
---|---|
bin | 1100001001011001011010… |
… | …0111011100001010111011 |
3 | 1202021210002100110112020212 |
4 | 3002112112213130022323 |
5 | 3222304212020312132 |
6 | 44223245135141335 |
7 | 2545623504663503 |
oct | 302262647341273 |
9 | 52253070415225 |
10 | 13355580244667 |
11 | 428a0849614a1 |
12 | 15b849897484b |
13 | 75b56c68525b |
14 | 3425b0a3ca03 |
15 | 18262155b5b2 |
hex | c25969dc2bb |
13355580244667 has 4 divisors (see below), whose sum is σ = 13355711439120. Its totient is φ = 13355449050216.
The previous prime is 13355580244603. The next prime is 13355580244753. The reversal of 13355580244667 is 76644208555331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13355580244667 - 26 = 13355580244603 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13355580274667) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65444408 + ... + 65648165.
It is an arithmetic number, because the mean of its divisors is an integer number (3338927859780).
Almost surely, 213355580244667 is an apocalyptic number.
13355580244667 is a deficient number, since it is larger than the sum of its proper divisors (131194453).
13355580244667 is a wasteful number, since it uses less digits than its factorization.
13355580244667 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131194452.
The product of its (nonzero) digits is 72576000, while the sum is 59.
Adding to 13355580244667 its reverse (76644208555331), we get a palindrome (89999788799998).
The spelling of 13355580244667 in words is "thirteen trillion, three hundred fifty-five billion, five hundred eighty million, two hundred forty-four thousand, six hundred sixty-seven".
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