Base | Representation |
---|---|
bin | 11110010111101000001110… |
… | …101111111111100111010001 |
3 | 122111220200222021201011010110 |
4 | 132113220032233333213101 |
5 | 120001312401422331421 |
6 | 1152022551202151533 |
7 | 40063522456324140 |
oct | 3627501657774721 |
9 | 574820867634113 |
10 | 133565140433361 |
11 | 3961572681409a |
12 | 12b9199b3525a9 |
13 | 596b1a594b280 |
14 | 24da831747757 |
15 | 10695085b9a76 |
hex | 797a0ebff9d1 |
133565140433361 has 16 divisors (see below), whose sum is σ = 219183820198784. Its totient is φ = 70451942206464.
The previous prime is 133565140433323. The next prime is 133565140433363. The reversal of 133565140433361 is 163334041565331.
It is not a de Polignac number, because 133565140433361 - 218 = 133565140171217 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133565140433361.
It is not an unprimeable number, because it can be changed into a prime (133565140433363) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 244624799056 + ... + 244624799601.
It is an arithmetic number, because the mean of its divisors is an integer number (13698988762424).
Almost surely, 2133565140433361 is an apocalyptic number.
It is an amenable number.
133565140433361 is a deficient number, since it is larger than the sum of its proper divisors (85618679765423).
133565140433361 is a wasteful number, since it uses less digits than its factorization.
133565140433361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 489249598680.
The product of its (nonzero) digits is 3499200, while the sum is 48.
Adding to 133565140433361 its reverse (163334041565331), we get a palindrome (296899181998692).
The spelling of 133565140433361 in words is "one hundred thirty-three trillion, five hundred sixty-five billion, one hundred forty million, four hundred thirty-three thousand, three hundred sixty-one".
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