Base | Representation |
---|---|
bin | 11110010111101000100111… |
… | …111010100101011100011001 |
3 | 122111220202001201011110222001 |
4 | 132113220213322211130121 |
5 | 120001314233013441103 |
6 | 1152023101123401001 |
7 | 40063536104115550 |
oct | 3627504772453431 |
9 | 574822051143861 |
10 | 133565562640153 |
11 | 39615923077326 |
12 | 12b91a98823161 |
13 | 596b242266587 |
14 | 24da87184cd97 |
15 | 10695306b801d |
hex | 797a27ea5719 |
133565562640153 has 8 divisors (see below), whose sum is σ = 157910024796480. Its totient is φ = 110537017357200.
The previous prime is 133565562640151. The next prime is 133565562640207. The reversal of 133565562640153 is 351046265565331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 133565562640153 - 21 = 133565562640151 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133565562640094 and 133565562640103.
It is not an unprimeable number, because it can be changed into a prime (133565562640151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 328979218123 + ... + 328979218528.
It is an arithmetic number, because the mean of its divisors is an integer number (19738753099560).
Almost surely, 2133565562640153 is an apocalyptic number.
It is an amenable number.
133565562640153 is a deficient number, since it is larger than the sum of its proper divisors (24344462156327).
133565562640153 is an equidigital number, since it uses as much as digits as its factorization.
133565562640153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 657958436687.
The product of its (nonzero) digits is 29160000, while the sum is 55.
The spelling of 133565562640153 in words is "one hundred thirty-three trillion, five hundred sixty-five billion, five hundred sixty-two million, six hundred forty thousand, one hundred fifty-three".
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