Base | Representation |
---|---|
bin | 11110011000010011111011… |
… | …001010001111100101000001 |
3 | 122112002012001221101201121220 |
4 | 132120103323022033211001 |
5 | 120003044442420113213 |
6 | 1152100310434305253 |
7 | 40100103212464326 |
oct | 3630237312174501 |
9 | 575065057351556 |
10 | 133612056410433 |
11 | 39633611648067 |
12 | 12b9aab3428229 |
13 | 5972741798253 |
14 | 24dcc0263cb4d |
15 | 106a85231ee23 |
hex | 7984fb28f941 |
133612056410433 has 8 divisors (see below), whose sum is σ = 178225184570496. Its totient is φ = 89036816262000.
The previous prime is 133612056410431. The next prime is 133612056410447. The reversal of 133612056410433 is 334014650216331.
133612056410433 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 133612056410433 - 21 = 133612056410431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133612056410431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9471994678 + ... + 9472008783.
It is an arithmetic number, because the mean of its divisors is an integer number (22278148071312).
Almost surely, 2133612056410433 is an apocalyptic number.
It is an amenable number.
133612056410433 is a deficient number, since it is larger than the sum of its proper divisors (44613128160063).
133612056410433 is a wasteful number, since it uses less digits than its factorization.
133612056410433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18944005815.
The product of its (nonzero) digits is 466560, while the sum is 42.
The spelling of 133612056410433 in words is "one hundred thirty-three trillion, six hundred twelve billion, fifty-six million, four hundred ten thousand, four hundred thirty-three".
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