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133628013643 = 367364109029
BaseRepresentation
bin111110001110011011…
…0011010110001001011
3110202220202200102201111
41330130312122301023
54142132232414033
6141215440031151
712440266242415
oct1743466326113
9422822612644
10133628013643
1151742591513
1221a939024b7
13c7a7712777
14667926b9b5
15372160a7cd
hex1f1cd9ac4b

133628013643 has 4 divisors (see below), whose sum is σ = 133992123040. Its totient is φ = 133263904248.

The previous prime is 133628013637. The next prime is 133628013667. The reversal of 133628013643 is 346310826331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133628013643 - 217 = 133627882571 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133628013596 and 133628013605.

It is not an unprimeable number, because it can be changed into a prime (133628014643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182054148 + ... + 182054881.

It is an arithmetic number, because the mean of its divisors is an integer number (33498030760).

Almost surely, 2133628013643 is an apocalyptic number.

133628013643 is a deficient number, since it is larger than the sum of its proper divisors (364109397).

133628013643 is an equidigital number, since it uses as much as digits as its factorization.

133628013643 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 364109396.

The product of its (nonzero) digits is 186624, while the sum is 40.

Adding to 133628013643 its reverse (346310826331), we get a palindrome (479938839974).

The spelling of 133628013643 in words is "one hundred thirty-three billion, six hundred twenty-eight million, thirteen thousand, six hundred forty-three".

Divisors: 1 367 364109029 133628013643