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1336400153 = 11121490923
BaseRepresentation
bin100111110100111…
…1101100100011001
310110010200011100222
41033221331210121
510214104301103
6340335405425
745055133234
oct11751754431
93403604328
101336400153
116263aa240
12313683875
13183b4112a
14c96b841b
157c4d0638
hex4fa7d919

1336400153 has 4 divisors (see below), whose sum is σ = 1457891088. Its totient is φ = 1214909220.

The previous prime is 1336400083. The next prime is 1336400161. The reversal of 1336400153 is 3510046331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1336400153 - 224 = 1319622937 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1336405153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60745451 + ... + 60745472.

It is an arithmetic number, because the mean of its divisors is an integer number (364472772).

Almost surely, 21336400153 is an apocalyptic number.

It is an amenable number.

1336400153 is a deficient number, since it is larger than the sum of its proper divisors (121490935).

1336400153 is a wasteful number, since it uses less digits than its factorization.

1336400153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121490934.

The product of its (nonzero) digits is 3240, while the sum is 26.

The square root of 1336400153 is about 36556.8072046780. The cubic root of 1336400153 is about 1101.4856380781.

Adding to 1336400153 its reverse (3510046331), we get a palindrome (4846446484).

The spelling of 1336400153 in words is "one billion, three hundred thirty-six million, four hundred thousand, one hundred fifty-three".

Divisors: 1 11 121490923 1336400153