Base | Representation |
---|---|
bin | 11000111001000111… |
… | …11110101111111001 |
3 | 1021111100220102021021 |
4 | 30130203332233321 |
5 | 204332202032433 |
6 | 10050034542441 |
7 | 652113640663 |
oct | 143443765771 |
9 | 37440812237 |
10 | 13364095993 |
11 | 5738758136 |
12 | 270b737a21 |
13 | 134c951c11 |
14 | 90ac65533 |
15 | 5333c222d |
hex | 31c8febf9 |
13364095993 has 4 divisors (see below), whose sum is σ = 13399357840. Its totient is φ = 13328834148.
The previous prime is 13364095991. The next prime is 13364096003. The reversal of 13364095993 is 39959046331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13364095993 - 21 = 13364095991 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13364095993.
It is not an unprimeable number, because it can be changed into a prime (13364095991) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17630355 + ... + 17631112.
It is an arithmetic number, because the mean of its divisors is an integer number (3349839460).
Almost surely, 213364095993 is an apocalyptic number.
It is an amenable number.
13364095993 is a deficient number, since it is larger than the sum of its proper divisors (35261847).
13364095993 is an equidigital number, since it uses as much as digits as its factorization.
13364095993 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35261846.
The product of its (nonzero) digits is 2361960, while the sum is 52.
The spelling of 13364095993 in words is "thirteen billion, three hundred sixty-four million, ninety-five thousand, nine hundred ninety-three".
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