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13371113 = 71910159
BaseRepresentation
bin110011000000…
…011011101001
3221011022201102
4303000123221
511410333423
61154331145
7221436560
oct63003351
927138642
1013371113
117602a08
124589ab5
132a02102
141ac0bd7
151291c28
hexcc06e9

13371113 has 4 divisors (see below), whose sum is σ = 15281280. Its totient is φ = 11460948.

The previous prime is 13371109. The next prime is 13371131. The reversal of 13371113 is 31117331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31117331 = 74445333.

It is a cyclic number.

It is not a de Polignac number, because 13371113 - 22 = 13371109 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13371103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 955073 + ... + 955086.

It is an arithmetic number, because the mean of its divisors is an integer number (3820320).

Almost surely, 213371113 is an apocalyptic number.

It is an amenable number.

13371113 is a deficient number, since it is larger than the sum of its proper divisors (1910167).

13371113 is an equidigital number, since it uses as much as digits as its factorization.

13371113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1910166.

The product of its digits is 189, while the sum is 20.

The square root of 13371113 is about 3656.6532512668. The cubic root of 13371113 is about 237.3499728388.

Adding to 13371113 its reverse (31117331), we get a palindrome (44488444).

The spelling of 13371113 in words is "thirteen million, three hundred seventy-one thousand, one hundred thirteen".

Divisors: 1 7 1910159 13371113