Base | Representation |
---|---|
bin | 111110010011101000… |
… | …0111111110001011001 |
3 | 110210100221111010012201 |
4 | 1330213100333301121 |
5 | 4143012001044423 |
6 | 141245041210201 |
7 | 12444520431061 |
oct | 1744720776131 |
9 | 423327433181 |
10 | 133802753113 |
11 | 518221908a7 |
12 | 21b22330961 |
13 | c8049940c3 |
14 | 66945563a1 |
15 | 3731b252ad |
hex | 1f2743fc59 |
133802753113 has 4 divisors (see below), whose sum is σ = 134113200768. Its totient is φ = 133492305460.
The previous prime is 133802753087. The next prime is 133802753137. The reversal of 133802753113 is 311357208331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311357208331 = 13 ⋅23950554487.
It is a cyclic number.
It is not a de Polignac number, because 133802753113 - 25 = 133802753081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133802753153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155223181 + ... + 155224042.
It is an arithmetic number, because the mean of its divisors is an integer number (33528300192).
Almost surely, 2133802753113 is an apocalyptic number.
It is an amenable number.
133802753113 is a deficient number, since it is larger than the sum of its proper divisors (310447655).
133802753113 is an equidigital number, since it uses as much as digits as its factorization.
133802753113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 310447654.
The product of its (nonzero) digits is 45360, while the sum is 37.
The spelling of 133802753113 in words is "one hundred thirty-three billion, eight hundred two million, seven hundred fifty-three thousand, one hundred thirteen".
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