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133934444439331 = 709188906127559
BaseRepresentation
bin11110011101000000001010…
…111110111110011100100011
3122120020000012201100110102111
4132131000022332332130203
5120023340220234024311
61152504345004500151
740132305250511164
oct3635001276763443
9576200181313374
10133934444439331
1139748308249888
121303148654a657
135996c6b958623
142510666c8b76b
151073e20208d21
hex79d00afbe723

133934444439331 has 4 divisors (see below), whose sum is σ = 134123350567600. Its totient is φ = 133745538311064.

The previous prime is 133934444439311. The next prime is 133934444439337.

133934444439331 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133934444439331 - 215 = 133934444406563 is a prime.

It is a super-2 number, since 2×1339344444393312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133934444439337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94453063071 + ... + 94453064488.

It is an arithmetic number, because the mean of its divisors is an integer number (33530837641900).

Almost surely, 2133934444439331 is an apocalyptic number.

133934444439331 is a deficient number, since it is larger than the sum of its proper divisors (188906128269).

133934444439331 is an equidigital number, since it uses as much as digits as its factorization.

133934444439331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188906128268.

The product of its digits is 60466176, while the sum is 58.

The spelling of 133934444439331 in words is "one hundred thirty-three trillion, nine hundred thirty-four billion, four hundred forty-four million, four hundred thirty-nine thousand, three hundred thirty-one".

Divisors: 1 709 188906127559 133934444439331