Base | Representation |
---|---|
bin | 1111111110001… |
… | …10101011100001 |
3 | 100100010001001022 |
4 | 13333012223201 |
5 | 233244423240 |
6 | 21143415225 |
7 | 3214556555 |
oct | 777065341 |
9 | 310101038 |
10 | 133982945 |
11 | 696a2408 |
12 | 38a54515 |
13 | 219b1665 |
14 | 13b19865 |
15 | bb689b5 |
hex | 7fc6ae1 |
133982945 has 4 divisors (see below), whose sum is σ = 160779540. Its totient is φ = 107186352.
The previous prime is 133982911. The next prime is 133982963. The reversal of 133982945 is 549289331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 92083216 + 41899729 = 9596^2 + 6473^2 .
It is a cyclic number.
It is not a de Polignac number, because 133982945 - 214 = 133966561 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133982896 and 133982905.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13398290 + ... + 13398299.
It is an arithmetic number, because the mean of its divisors is an integer number (40194885).
Almost surely, 2133982945 is an apocalyptic number.
It is an amenable number.
133982945 is a deficient number, since it is larger than the sum of its proper divisors (26796595).
133982945 is an equidigital number, since it uses as much as digits as its factorization.
133982945 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26796594.
The product of its digits is 233280, while the sum is 44.
The square root of 133982945 is about 11575.1002155489. The cubic root of 133982945 is about 511.7012837311.
The spelling of 133982945 in words is "one hundred thirty-three million, nine hundred eighty-two thousand, nine hundred forty-five".
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