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13400025545 = 55008753507
BaseRepresentation
bin11000111101011010…
…00010100111001001
31021120212111211100102
430132231002213021
5204420401304140
610053401015145
7653031223604
oct143655024711
937525454312
1013400025545
115756a68585
12271b7844b5
131357221aca
1491193933b
1553661ce15
hex31eb429c9

13400025545 has 8 divisors (see below), whose sum is σ = 16080652224. Its totient is φ = 10719606064.

The previous prime is 13400025533. The next prime is 13400025547. The reversal of 13400025545 is 54552000431.

13400025545 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13400025545 - 216 = 13399960009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13400025547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 223682 + ... + 277188.

It is an arithmetic number, because the mean of its divisors is an integer number (2010081528).

Almost surely, 213400025545 is an apocalyptic number.

It is an amenable number.

13400025545 is a deficient number, since it is larger than the sum of its proper divisors (2680626679).

13400025545 is an equidigital number, since it uses as much as digits as its factorization.

13400025545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103599.

The product of its (nonzero) digits is 12000, while the sum is 29.

Adding to 13400025545 its reverse (54552000431), we get a palindrome (67952025976).

The spelling of 13400025545 in words is "thirteen billion, four hundred million, twenty-five thousand, five hundred forty-five".

Divisors: 1 5 50087 53507 250435 267535 2680005109 13400025545