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1340020203 = 3446673401
BaseRepresentation
bin100111111011111…
…0001010111101011
310110101111002010220
41033313301113223
510221021121303
6340545141123
745130661304
oct11767612753
93411432126
101340020203
11628452015
1231492a7a3
1318480aa82
14c9d7b7ab
157c998053
hex4fdf15eb

1340020203 has 4 divisors (see below), whose sum is σ = 1786693608. Its totient is φ = 893346800.

The previous prime is 1340020159. The next prime is 1340020207. The reversal of 1340020203 is 3020200431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340020203 - 210 = 1340019179 is a prime.

It is a super-2 number, since 2×13400202032 = 3591308288896322418, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1340020207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223336698 + ... + 223336703.

It is an arithmetic number, because the mean of its divisors is an integer number (446673402).

Almost surely, 21340020203 is an apocalyptic number.

1340020203 is a deficient number, since it is larger than the sum of its proper divisors (446673405).

1340020203 is an equidigital number, since it uses as much as digits as its factorization.

1340020203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446673404.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 1340020203 is about 36606.2863863572. The cubic root of 1340020203 is about 1102.4793120382.

Adding to 1340020203 its reverse (3020200431), we get a palindrome (4360220634).

The spelling of 1340020203 in words is "one billion, three hundred forty million, twenty thousand, two hundred three".

Divisors: 1 3 446673401 1340020203