Base | Representation |
---|---|
bin | 11000111101011101… |
… | …01001000011011001 |
3 | 1021120220022010221011 |
4 | 30132232221003121 |
5 | 204421003221040 |
6 | 10053414013521 |
7 | 653034622123 |
oct | 143656510331 |
9 | 37526263834 |
10 | 13400445145 |
11 | 575722485a |
12 | 271b9472a1 |
13 | 135733aaa9 |
14 | 911a08213 |
15 | 5366a23ea |
hex | 31eba90d9 |
13400445145 has 4 divisors (see below), whose sum is σ = 16080534180. Its totient is φ = 10720356112.
The previous prime is 13400445133. The next prime is 13400445181. The reversal of 13400445145 is 54154400431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54154400431 = 31663 ⋅1710337.
It can be written as a sum of positive squares in 2 ways, for example, as 8312333584 + 5088111561 = 91172^2 + 71331^2 .
It is a cyclic number.
It is not a de Polignac number, because 13400445145 - 213 = 13400436953 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340044510 + ... + 1340044519.
It is an arithmetic number, because the mean of its divisors is an integer number (4020133545).
Almost surely, 213400445145 is an apocalyptic number.
It is an amenable number.
13400445145 is a deficient number, since it is larger than the sum of its proper divisors (2680089035).
13400445145 is an equidigital number, since it uses as much as digits as its factorization.
13400445145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2680089034.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 13400445145 its reverse (54154400431), we get a palindrome (67554845576).
The spelling of 13400445145 in words is "thirteen billion, four hundred million, four hundred forty-five thousand, one hundred forty-five".
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