Base | Representation |
---|---|
bin | 11110011110000001111010… |
… | …111111100011010100111001 |
3 | 122120110202102212012210100220 |
4 | 132132001322333203110321 |
5 | 120031014312014142241 |
6 | 1153001022243250253 |
7 | 40140354614403660 |
oct | 3636017277432471 |
9 | 576422385183326 |
10 | 134005043115321 |
11 | 39775246374aa4 |
12 | 130430a9979989 |
13 | 59a0810127011 |
14 | 2513c431c3dd7 |
15 | 1075ba3175166 |
hex | 79e07afe3539 |
134005043115321 has 8 divisors (see below), whose sum is σ = 204198160937664. Its totient is φ = 76574310351600.
The previous prime is 134005043115233. The next prime is 134005043115367. The reversal of 134005043115321 is 123511340500431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 134005043115321 - 214 = 134005043098937 is a prime.
It is not an unprimeable number, because it can be changed into a prime (134005043165321) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3190596264630 + ... + 3190596264671.
It is an arithmetic number, because the mean of its divisors is an integer number (25524770117208).
Almost surely, 2134005043115321 is an apocalyptic number.
It is an amenable number.
134005043115321 is a deficient number, since it is larger than the sum of its proper divisors (70193117822343).
134005043115321 is an equidigital number, since it uses as much as digits as its factorization.
134005043115321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6381192529311.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 134005043115321 its reverse (123511340500431), we get a palindrome (257516383615752).
The spelling of 134005043115321 in words is "one hundred thirty-four trillion, five billion, forty-three million, one hundred fifteen thousand, three hundred twenty-one".
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