Base | Representation |
---|---|
bin | 111110011001101010… |
… | …1010010001000101011 |
3 | 110210220001102122221011 |
4 | 1330303111102020223 |
5 | 4143420313002444 |
6 | 141321112324351 |
7 | 12452526302326 |
oct | 1746325221053 |
9 | 423801378834 |
10 | 134005203499 |
11 | 51916497872 |
12 | 21b7a0a36b7 |
13 | c8378c882b |
14 | 66b33b57bd |
15 | 37447b5734 |
hex | 1f3355222b |
134005203499 has 4 divisors (see below), whose sum is σ = 134016870664. Its totient is φ = 133993536336.
The previous prime is 134005203473. The next prime is 134005203517. The reversal of 134005203499 is 994302500431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134005203499 - 25 = 134005203467 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134005203599) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5816337 + ... + 5839330.
It is an arithmetic number, because the mean of its divisors is an integer number (33504217666).
Almost surely, 2134005203499 is an apocalyptic number.
134005203499 is a deficient number, since it is larger than the sum of its proper divisors (11667165).
134005203499 is a wasteful number, since it uses less digits than its factorization.
134005203499 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11667164.
The product of its (nonzero) digits is 116640, while the sum is 40.
The spelling of 134005203499 in words is "one hundred thirty-four billion, five million, two hundred three thousand, four hundred ninety-nine".
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