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13401001331 = 411667196073
BaseRepresentation
bin11000111101100001…
…10000110101110011
31021120221100101212122
430132300300311303
5204421124020311
610053433544455
7653042426504
oct143660606563
937527311778
1013401001331
115757574713
12271bb7512b
1313574a3cb3
14911b10bab
155367620db
hex31ec30d73

13401001331 has 8 divisors (see below), whose sum is σ = 13736160144. Its totient is φ = 13066238080.

The previous prime is 13401001319. The next prime is 13401001333. The reversal of 13401001331 is 13310010431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13401001331 - 210 = 13401000307 is a prime.

It is a super-2 number, since 2×134010013312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401001333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29690 + ... + 166383.

It is an arithmetic number, because the mean of its divisors is an integer number (1717020018).

Almost surely, 213401001331 is an apocalyptic number.

13401001331 is a deficient number, since it is larger than the sum of its proper divisors (335158813).

13401001331 is a wasteful number, since it uses less digits than its factorization.

13401001331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 197781.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13401001331 its reverse (13310010431), we get a palindrome (26711011762).

It can be divided in two parts, 1340100 and 1331, that added together give a palindrome (1341431).

The spelling of 13401001331 in words is "thirteen billion, four hundred one million, one thousand, three hundred thirty-one".

Divisors: 1 41 1667 68347 196073 8038993 326853691 13401001331