1340100641 has 4 divisors (see below), whose sum is σ = 1461927984. Its totient is φ = 1218273300.

The previous prime is 1340100617. The next prime is 1340100673. The reversal of 1340100641 is 1460010431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1460010431 = 11 ⋅132728221.

It is a cyclic number.

It is not a de Polignac number, because 1340100641 - 2¹⁸ = 1339838497 is a prime.

It is a super-2 number, since 2×1340100641² = 3591739456017221762, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1340100841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60913655 + ... + 60913676.

It is an arithmetic number, because the mean of its divisors is an integer number (365481996).

Almost surely, 2^1340100641 is an apocalyptic number.

1340100641 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1340100641 is a deficient number, since it is larger than the sum of its proper divisors (121827343).

1340100641 is a wasteful number, since it uses less digits than its factorization.

1340100641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121827342.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 1340100641 is about 36607.3850609409. The cubic root of 1340100641 is about 1102.5013712719.

The spelling of 1340100641 in words is "one billion, three hundred forty million, one hundred thousand, six hundred forty-one".