13401040103211 has 16 divisors (see below), whose sum is σ = 18862680470400. Its totient is φ = 8439423392448.

The previous prime is 13401040103179. The next prime is 13401040103219. The reversal of 13401040103211 is 11230104010431.

It is not a de Polignac number, because 13401040103211 - 2⁵ = 13401040103179 is a prime.

It is a super-3 number, since 3×13401040103211³ (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (13401040103219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 338749626 + ... + 338789183.

It is an arithmetic number, because the mean of its divisors is an integer number (1178917529400).

Almost surely, 2^{13401040103211} is an apocalyptic number.

13401040103211 is a deficient number, since it is larger than the sum of its proper divisors (5461640367189).

13401040103211 is a wasteful number, since it uses less digits than its factorization.

13401040103211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 677539178.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 13401040103211 its reverse (11230104010431), we get a palindrome (24631144113642).

The spelling of 13401040103211 in words is "thirteen trillion, four hundred one billion, forty million, one hundred three thousand, two hundred eleven".