134010441001 has 4 divisors (see below), whose sum is σ = 134012491600. Its totient is φ = 134008390404.

The previous prime is 134010440987. The next prime is 134010441053. The reversal of 134010441001 is 100144010431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134010441001 - 2¹¹ = 134010438953 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134010441001.

It is not an unprimeable number, because it can be changed into a prime (134010441101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 923931 + ... + 1059088.

It is an arithmetic number, because the mean of its divisors is an integer number (33503122900).

Almost surely, 2^134010441001 is an apocalyptic number.

It is an amenable number.

134010441001 is a deficient number, since it is larger than the sum of its proper divisors (2050599).

134010441001 is an equidigital number, since it uses as much as digits as its factorization.

134010441001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2050598.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 134010441001 its reverse (100144010431), we get a palindrome (234154451432).

The spelling of 134010441001 in words is "one hundred thirty-four billion, ten million, four hundred forty-one thousand, one".