1340106614153 has 4 divisors (see below), whose sum is σ = 1340266864848. Its totient is φ = 1339946363460.

The previous prime is 1340106614141. The next prime is 1340106614207. The reversal of 1340106614153 is 3514166010431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340106614153 - 2¹² = 1340106610057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340106614953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80112803 + ... + 80129528.

It is an arithmetic number, because the mean of its divisors is an integer number (335066716212).

Almost surely, 2^{1340106614153} is an apocalyptic number.

It is an amenable number.

1340106614153 is a deficient number, since it is larger than the sum of its proper divisors (160250695).

1340106614153 is an equidigital number, since it uses as much as digits as its factorization.

1340106614153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 160250694.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 1340106614153 in words is "one trillion, three hundred forty billion, one hundred six million, six hundred fourteen thousand, one hundred fifty-three".