Base | Representation |
---|---|
bin | 1100001100000011000001… |
… | …1111001110011101000011 |
3 | 1202110010121111110200122212 |
4 | 3003000300133032131003 |
5 | 3224030434013034210 |
6 | 44300215143052335 |
7 | 2552125014616535 |
oct | 303006037163503 |
9 | 52403544420585 |
10 | 13401111455555 |
11 | 42a741a0610aa |
12 | 16052851410ab |
13 | 762947658665 |
14 | 34488da69855 |
15 | 1838d892a805 |
hex | c30307ce743 |
13401111455555 has 4 divisors (see below), whose sum is σ = 16081333746672. Its totient is φ = 10720889164440.
The previous prime is 13401111455447. The next prime is 13401111455573. The reversal of 13401111455555 is 55555411110431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13401111455555 - 28 = 13401111455299 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340111145551 + ... + 1340111145560.
It is an arithmetic number, because the mean of its divisors is an integer number (4020333436668).
Almost surely, 213401111455555 is an apocalyptic number.
13401111455555 is a deficient number, since it is larger than the sum of its proper divisors (2680222291117).
13401111455555 is an equidigital number, since it uses as much as digits as its factorization.
13401111455555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2680222291116.
The product of its (nonzero) digits is 150000, while the sum is 41.
Adding to 13401111455555 its reverse (55555411110431), we get a palindrome (68956522565986).
The spelling of 13401111455555 in words is "thirteen trillion, four hundred one billion, one hundred eleven million, four hundred fifty-five thousand, five hundred fifty-five".
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