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1340113233 = 31319338669
BaseRepresentation
bin100111111100000…
…1000000101010001
310110101122210202110
41033320020011101
510221032110413
6340551135533
745131526444
oct11770100521
93411583673
101340113233
116285059a8
123149745a9
13184841214
14c9da365b
157c9b58c3
hex4fe08151

1340113233 has 8 divisors (see below), whose sum is σ = 1788177600. Its totient is φ = 892728848.

The previous prime is 1340113231. The next prime is 1340113237. The reversal of 1340113233 is 3323110431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340113233 - 21 = 1340113231 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1340113231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 165378 + ... + 173291.

It is an arithmetic number, because the mean of its divisors is an integer number (223522200).

Almost surely, 21340113233 is an apocalyptic number.

It is an amenable number.

1340113233 is a deficient number, since it is larger than the sum of its proper divisors (448064367).

1340113233 is a wasteful number, since it uses less digits than its factorization.

1340113233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 339991.

The product of its (nonzero) digits is 648, while the sum is 21.

The square root of 1340113233 is about 36607.5570476917. The cubic root of 1340113233 is about 1102.5048244090.

Adding to 1340113233 its reverse (3323110431), we get a palindrome (4663223664).

The spelling of 1340113233 in words is "one billion, three hundred forty million, one hundred thirteen thousand, two hundred thirty-three".

Divisors: 1 3 1319 3957 338669 1016007 446704411 1340113233