13401141041 has 4 divisors (see below), whose sum is σ = 13439761392. Its totient is φ = 13362520692.

The previous prime is 13401141031. The next prime is 13401141053. The reversal of 13401141041 is 14014110431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14014110431 = 3929 ⋅3566839.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401141041 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13401141031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19309655 + ... + 19310348.

It is an arithmetic number, because the mean of its divisors is an integer number (3359940348).

Almost surely, 2^13401141041 is an apocalyptic number.

It is an amenable number.

13401141041 is a deficient number, since it is larger than the sum of its proper divisors (38620351).

13401141041 is an equidigital number, since it uses as much as digits as its factorization.

13401141041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38620350.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 13401141041 its reverse (14014110431), we get a palindrome (27415251472).

The spelling of 13401141041 in words is "thirteen billion, four hundred one million, one hundred forty-one thousand, forty-one".