13401142041433 has 8 divisors (see below), whose sum is σ = 13426303542336. Its totient is φ = 13376003917200.

The previous prime is 13401142041347. The next prime is 13401142041437. The reversal of 13401142041433 is 33414024110431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13401142041433 - 2¹³ = 13401142033241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13401142041395 and 13401142041404.

It is not an unprimeable number, because it can be changed into a prime (13401142041437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4696341 + ... + 6989842.

It is an arithmetic number, because the mean of its divisors is an integer number (1678287942792).

Almost surely, 2^{13401142041433} is an apocalyptic number.

It is an amenable number.

13401142041433 is a deficient number, since it is larger than the sum of its proper divisors (25161500903).

13401142041433 is a wasteful number, since it uses less digits than its factorization.

13401142041433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11688335.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13401142041433 its reverse (33414024110431), we get a palindrome (46815166151864).

The spelling of 13401142041433 in words is "thirteen trillion, four hundred one billion, one hundred forty-two million, forty-one thousand, four hundred thirty-three".