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134011501851155 = 526802300370231
BaseRepresentation
bin11110011110000111111011…
…111101101011001000010011
3122120111101002222110120022012
4132132013323331223020103
5120031121023433214110
61153004011204333135
740141003641634415
oct3636077375531023
9576441088416265
10134011501851155
1139777a60138905
12130443b09a41ab
1359a12cc25aab6
142514296cc69b5
151075e301c4905
hex79e1fbf6b213

134011501851155 has 4 divisors (see below), whose sum is σ = 160813802221392. Its totient is φ = 107209201480920.

The previous prime is 134011501851133. The next prime is 134011501851167. The reversal of 134011501851155 is 551158105110431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 134011501851155 - 220 = 134011500802579 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13401150185111 + ... + 13401150185120.

It is an arithmetic number, because the mean of its divisors is an integer number (40203450555348).

Almost surely, 2134011501851155 is an apocalyptic number.

134011501851155 is a deficient number, since it is larger than the sum of its proper divisors (26802300370237).

134011501851155 is an equidigital number, since it uses as much as digits as its factorization.

134011501851155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26802300370236.

The product of its (nonzero) digits is 60000, while the sum is 41.

Adding to 134011501851155 its reverse (551158105110431), we get a palindrome (685169606961586).

The spelling of 134011501851155 in words is "one hundred thirty-four trillion, eleven billion, five hundred one million, eight hundred fifty-one thousand, one hundred fifty-five".

Divisors: 1 5 26802300370231 134011501851155