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1340120010121 = 3762927575579
BaseRepresentation
bin10011100000000101011…
…000001000110110001001
311202010002021020010122221
4103200011120020312021
5133424031210310441
62503350450414041
7165551265065044
oct23400530106611
94663067203587
101340120010121
11477383899652
12197883591321
13994acca83b9
1448c0da75c5b
1524cd62158d1
hex13805608d89

1340120010121 has 8 divisors (see below), whose sum is σ = 1376363733120. Its totient is φ = 1303877564208.

The previous prime is 1340120010043. The next prime is 1340120010139. The reversal of 1340120010121 is 1210100210431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340120010121 - 29 = 1340120009609 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340120010095 and 1340120010104.

It is not an unprimeable number, because it can be changed into a prime (1340120010721) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2040510 + ... + 2616088.

It is an arithmetic number, because the mean of its divisors is an integer number (172045466640).

Almost surely, 21340120010121 is an apocalyptic number.

It is an amenable number.

1340120010121 is a deficient number, since it is larger than the sum of its proper divisors (36243722999).

1340120010121 is an equidigital number, since it uses as much as digits as its factorization.

1340120010121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 638543.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1340120010121 its reverse (1210100210431), we get a palindrome (2550220220552).

The spelling of 1340120010121 in words is "one trillion, three hundred forty billion, one hundred twenty million, ten thousand, one hundred twenty-one".

Divisors: 1 37 62927 575579 2328299 21296423 36219459733 1340120010121