Base | Representation |
---|---|
bin | 11110011110001000011010… |
… | …100100110000001100100011 |
3 | 122120111102102202211011100100 |
4 | 132132020122210300030203 |
5 | 120031123101421141003 |
6 | 1153004134151553443 |
7 | 40141022446061361 |
oct | 3636103244601443 |
9 | 576442382734310 |
10 | 134012015412003 |
11 | 397781a4017763 |
12 | 1304451498b883 |
13 | 59a1381780461 |
14 | 25143051ac631 |
15 | 1075e6031aba3 |
hex | 79e21a930323 |
134012015412003 has 6 divisors (see below), whose sum is σ = 193572911150684. Its totient is φ = 89341343607996.
The previous prime is 134012015411999. The next prime is 134012015412013. The reversal of 134012015412003 is 300214510210431.
134012015412003 is a `hidden beast` number, since 1 + 3 + 40 + 1 + 201 + 5 + 412 + 0 + 0 + 3 = 666.
It is not a de Polignac number, because 134012015412003 - 22 = 134012015411999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134012015412013) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7445111967325 + ... + 7445111967342.
Almost surely, 2134012015412003 is an apocalyptic number.
134012015412003 is a deficient number, since it is larger than the sum of its proper divisors (59560895738681).
134012015412003 is a wasteful number, since it uses less digits than its factorization.
134012015412003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14890223934673 (or 14890223934670 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 134012015412003 its reverse (300214510210431), we get a palindrome (434226525622434).
The spelling of 134012015412003 in words is "one hundred thirty-four trillion, twelve billion, fifteen million, four hundred twelve thousand, three".
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