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13401210400403 = 715667122196887
BaseRepresentation
bin1100001100000011011001…
…1000101010111010010011
31202110010212101122121110212
43003000312120222322103
53224031134330303103
644300233035514335
72552130325625510
oct303006630527223
952403771577425
1013401210400403
1142a746a9a1901
1216052b22b89ab
13762961cbcac7
1434489cc64307
151838e24727d8
hexc303662ae93

13401210400403 has 8 divisors (see below), whose sum is σ = 15316646729472. Its totient is φ = 11486018496456.

The previous prime is 13401210400381. The next prime is 13401210400511. The reversal of 13401210400403 is 30400401210431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13401210400403 - 214 = 13401210384019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401210400003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60988775 + ... + 61208112.

It is an arithmetic number, because the mean of its divisors is an integer number (1914580841184).

Almost surely, 213401210400403 is an apocalyptic number.

13401210400403 is a deficient number, since it is larger than the sum of its proper divisors (1915436329069).

13401210400403 is a wasteful number, since it uses less digits than its factorization.

13401210400403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122212561.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13401210400403 its reverse (30400401210431), we get a palindrome (43801611610834).

The spelling of 13401210400403 in words is "thirteen trillion, four hundred one billion, two hundred ten million, four hundred thousand, four hundred three".

Divisors: 1 7 15667 109669 122196887 855378209 1914458628629 13401210400403