13401213413123 has 16 divisors (see below), whose sum is σ = 13540984591200. Its totient is φ = 13261758048000.

The previous prime is 13401213413087. The next prime is 13401213413129. The reversal of 13401213413123 is 32131431210431.

It is a cyclic number.

It is not a de Polignac number, because 13401213413123 - 2¹⁸ = 13401213150979 is a prime.

It is a super-2 number, since 2×13401213413123² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401213413129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 316246565 + ... + 316288937.

It is an arithmetic number, because the mean of its divisors is an integer number (846311536950).

Almost surely, 2^{13401213413123} is an apocalyptic number.

13401213413123 is a deficient number, since it is larger than the sum of its proper divisors (139771178077).

13401213413123 is a wasteful number, since it uses less digits than its factorization.

13401213413123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46022.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13401213413123 its reverse (32131431210431), we get a palindrome (45532644623554).

The spelling of 13401213413123 in words is "thirteen trillion, four hundred one billion, two hundred thirteen million, four hundred thirteen thousand, one hundred twenty-three".