13401213502153 has 4 divisors (see below), whose sum is σ = 13402124110980. Its totient is φ = 13400302893328.

The previous prime is 13401213502133. The next prime is 13401213502163. The reversal of 13401213502153 is 35120531210431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4375346943289 + 9025866558864 = 2091733^2 + 3004308^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401213502153 - 2¹³ = 13401213493961 is a prime.

It is a super-3 number, since 3×13401213502153³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401213502133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455282338 + ... + 455311771.

It is an arithmetic number, because the mean of its divisors is an integer number (3350531027745).

Almost surely, 2^{13401213502153} is an apocalyptic number.

It is an amenable number.

13401213502153 is a deficient number, since it is larger than the sum of its proper divisors (910608827).

13401213502153 is an equidigital number, since it uses as much as digits as its factorization.

13401213502153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 910608826.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13401213502153 its reverse (35120531210431), we get a palindrome (48521744712584).

The spelling of 13401213502153 in words is "thirteen trillion, four hundred one billion, two hundred thirteen million, five hundred two thousand, one hundred fifty-three".