13401214334041 has 4 divisors (see below), whose sum is σ = 13401232108084. Its totient is φ = 13401196560000.

The previous prime is 13401214334023. The next prime is 13401214334093. The reversal of 13401214334041 is 14043341210431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7997584000000 + 5403630334041 = 2828000^2 + 2324571^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401214334041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13401214333994 and 13401214334012.

It is not an unprimeable number, because it can be changed into a prime (13401214332041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7703520 + ... + 9281521.

It is an arithmetic number, because the mean of its divisors is an integer number (3350308027021).

Almost surely, 2^{13401214334041} is an apocalyptic number.

It is an amenable number.

13401214334041 is a deficient number, since it is larger than the sum of its proper divisors (17774043).

13401214334041 is an equidigital number, since it uses as much as digits as its factorization.

13401214334041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17774042.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13401214334041 its reverse (14043341210431), we get a palindrome (27444555544472).

The spelling of 13401214334041 in words is "thirteen trillion, four hundred one billion, two hundred fourteen million, three hundred thirty-four thousand, forty-one".