1340123321 has 4 divisors (see below), whose sum is σ = 1386334500. Its totient is φ = 1293912144.

The previous prime is 1340123303. The next prime is 1340123353. The reversal of 1340123321 is 1233210431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 667447225 + 672676096 = 25835^2 + 25936^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340123321 - 2¹⁰ = 1340122297 is a prime.

It is a super-3 number, since 3×1340123321³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1340123293 and 1340123302.

It is not an unprimeable number, because it can be changed into a prime (1340123381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23105546 + ... + 23105603.

It is an arithmetic number, because the mean of its divisors is an integer number (346583625).

Almost surely, 2^1340123321 is an apocalyptic number.

It is an amenable number.

1340123321 is a deficient number, since it is larger than the sum of its proper divisors (46211179).

1340123321 is an equidigital number, since it uses as much as digits as its factorization.

1340123321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46211178.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 1340123321 is about 36607.6948331905. The cubic root of 1340123321 is about 1102.5075908521.

Adding to 1340123321 its reverse (1233210431), we get a palindrome (2573333752).

The spelling of 1340123321 in words is "one billion, three hundred forty million, one hundred twenty-three thousand, three hundred twenty-one".