1340131011 has 4 divisors (see below), whose sum is σ = 1786841352. Its totient is φ = 893420672.

The previous prime is 1340130973. The next prime is 1340131019. The reversal of 1340131011 is 1101310431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340131011 - 2⁶ = 1340130947 is a prime.

It is a super-2 number, since 2×1340131011² = 3591902253287764242, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1340131019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223355166 + ... + 223355171.

It is an arithmetic number, because the mean of its divisors is an integer number (446710338).

Almost surely, 2^1340131011 is an apocalyptic number.

1340131011 is a deficient number, since it is larger than the sum of its proper divisors (446710341).

1340131011 is an equidigital number, since it uses as much as digits as its factorization.

1340131011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 446710340.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 1340131011 is about 36607.7998656024. The cubic root of 1340131011 is about 1102.5096996797.

Adding to 1340131011 its reverse (1101310431), we get a palindrome (2441441442).

The spelling of 1340131011 in words is "one billion, three hundred forty million, one hundred thirty-one thousand, eleven".