Base | Representation |
---|---|
bin | 1100001100000011110001… |
… | …1100010010000100111011 |
3 | 1202110011010110211221101211 |
4 | 3003000330130102010323 |
5 | 3224031341333314210 |
6 | 44300251105423551 |
7 | 2552133001405150 |
oct | 303007434220473 |
9 | 52404113757354 |
10 | 13401312010555 |
11 | 42a7512293037 |
12 | 160532033abb7 |
13 | 76297a078461 |
14 | 3448ac554227 |
15 | 1838eb34438a |
hex | c303c71213b |
13401312010555 has 8 divisors (see below), whose sum is σ = 18378942185952. Its totient is φ = 9189471092928.
The previous prime is 13401312010531. The next prime is 13401312010571. The reversal of 13401312010555 is 55501021310431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13401312010555 - 221 = 13401309913403 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 191447314402 + ... + 191447314471.
It is an arithmetic number, because the mean of its divisors is an integer number (2297367773244).
Almost surely, 213401312010555 is an apocalyptic number.
13401312010555 is a deficient number, since it is larger than the sum of its proper divisors (4977630175397).
13401312010555 is an equidigital number, since it uses as much as digits as its factorization.
13401312010555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 382894628885.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 13401312010555 its reverse (55501021310431), we get a palindrome (68902333320986).
The spelling of 13401312010555 in words is "thirteen trillion, four hundred one billion, three hundred twelve million, ten thousand, five hundred fifty-five".
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