1340132002401 has 4 divisors (see below), whose sum is σ = 1786842669872. Its totient is φ = 893421334932.

The previous prime is 1340132002399. The next prime is 1340132002409. The reversal of 1340132002401 is 1042002310431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1340132002401 - 2¹ = 1340132002399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340132002409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223355333731 + ... + 223355333736.

It is an arithmetic number, because the mean of its divisors is an integer number (446710667468).

Almost surely, 2^{1340132002401} is an apocalyptic number.

It is an amenable number.

1340132002401 is a deficient number, since it is larger than the sum of its proper divisors (446710667471).

1340132002401 is an equidigital number, since it uses as much as digits as its factorization.

1340132002401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 446710667470.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1340132002401 its reverse (1042002310431), we get a palindrome (2382134312832).

The spelling of 1340132002401 in words is "one trillion, three hundred forty billion, one hundred thirty-two million, two thousand, four hundred one".