134013301001 has 4 divisors (see below), whose sum is σ = 141896436372. Its totient is φ = 126130165632.

The previous prime is 134013300991. The next prime is 134013301013. The reversal of 134013301001 is 100103310431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 102079611001 + 31933690000 = 319499^2 + 178700^2 .

It is a cyclic number.

It is not a de Polignac number, because 134013301001 - 2¹⁴ = 134013284617 is a prime.

It is a super-4 number, since 4×134013301001⁴ (a number of 46 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 7883135353 = 134013301001 / (1 + 3 + 4 + 0 + 1 + 3 + 3 + 0 + 1 + 0 + 0 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134013301091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3941567660 + ... + 3941567693.

It is an arithmetic number, because the mean of its divisors is an integer number (35474109093).

Almost surely, 2^134013301001 is an apocalyptic number.

It is an amenable number.

134013301001 is a deficient number, since it is larger than the sum of its proper divisors (7883135371).

134013301001 is an equidigital number, since it uses as much as digits as its factorization.

134013301001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7883135370.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 134013301001 its reverse (100103310431), we get a palindrome (234116611432).

The spelling of 134013301001 in words is "one hundred thirty-four billion, thirteen million, three hundred one thousand, one".