13401331040001 has 4 divisors (see below), whose sum is σ = 17868441386672. Its totient is φ = 8934220693332.

The previous prime is 13401331039939. The next prime is 13401331040033. The reversal of 13401331040001 is 10004013310431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13401331040001 - 2¹⁷ = 13401330908929 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13401331040001.

It is not an unprimeable number, because it can be changed into a prime (13401331060001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233555173331 + ... + 2233555173336.

It is an arithmetic number, because the mean of its divisors is an integer number (4467110346668).

Almost surely, 2^{13401331040001} is an apocalyptic number.

It is an amenable number.

13401331040001 is a deficient number, since it is larger than the sum of its proper divisors (4467110346671).

13401331040001 is an equidigital number, since it uses as much as digits as its factorization.

13401331040001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467110346670.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13401331040001 its reverse (10004013310431), we get a palindrome (23405344350432).

The spelling of 13401331040001 in words is "thirteen trillion, four hundred one billion, three hundred thirty-one million, forty thousand, one".