134013401 has 4 divisors (see below), whose sum is σ = 136210404. Its totient is φ = 131816400.

The previous prime is 134013389. The next prime is 134013409. The reversal of 134013401 is 104310431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 104310431 = 71 ⋅1469161.

It can be written as a sum of positive squares in 2 ways, for example, as 65934400 + 68079001 = 8120^2 + 8251^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134013401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134013401.

It is not an unprimeable number, because it can be changed into a prime (134013409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1098410 + ... + 1098531.

It is an arithmetic number, because the mean of its divisors is an integer number (34052601).

Almost surely, 2^134013401 is an apocalyptic number.

It is an amenable number.

134013401 is a deficient number, since it is larger than the sum of its proper divisors (2197003).

134013401 is an equidigital number, since it uses as much as digits as its factorization.

134013401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2197002.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 134013401 is about 11576.4157233576. The cubic root of 134013401 is about 511.7400528287.

Adding to 134013401 its reverse (104310431), we get a palindrome (238323832).

It can be divided in two parts, 1340 and 13401, that added together give a palindrome (14741).

The spelling of 134013401 in words is "one hundred thirty-four million, thirteen thousand, four hundred one".