1340150343555 has 8 divisors (see below), whose sum is σ = 2144240549712. Its totient is φ = 714746849888.

The previous prime is 1340150343547. The next prime is 1340150343569. The reversal of 1340150343555 is 5553430510431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340150343555 - 2³ = 1340150343547 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44671678104 + ... + 44671678133.

It is an arithmetic number, because the mean of its divisors is an integer number (268030068714).

Almost surely, 2^{1340150343555} is an apocalyptic number.

1340150343555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1340150343555 is a deficient number, since it is larger than the sum of its proper divisors (804090206157).

1340150343555 is an equidigital number, since it uses as much as digits as its factorization.

1340150343555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89343356245.

The product of its (nonzero) digits is 270000, while the sum is 39.

Adding to 1340150343555 its reverse (5553430510431), we get a palindrome (6893580853986).

The spelling of 1340150343555 in words is "one trillion, three hundred forty billion, one hundred fifty million, three hundred forty-three thousand, five hundred fifty-five".