1340154012523 has 4 divisors (see below), whose sum is σ = 1341170051760. Its totient is φ = 1339137973288.

The previous prime is 1340154012499. The next prime is 1340154012539. The reversal of 1340154012523 is 3252104510431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340154012523 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340154012563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508017640 + ... + 508020277.

It is an arithmetic number, because the mean of its divisors is an integer number (335292512940).

Almost surely, 2^{1340154012523} is an apocalyptic number.

1340154012523 is a deficient number, since it is larger than the sum of its proper divisors (1016039237).

1340154012523 is a wasteful number, since it uses less digits than its factorization.

1340154012523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1016039236.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1340154012523 its reverse (3252104510431), we get a palindrome (4592258522954).

The spelling of 1340154012523 in words is "one trillion, three hundred forty billion, one hundred fifty-four million, twelve thousand, five hundred twenty-three".