Base | Representation |
---|---|
bin | 10011100000001010010… |
… | …001110010111011010011 |
3 | 11202010021222221112000022 |
4 | 103200022101302323103 |
5 | 133424213232433210 |
6 | 2503402545014055 |
7 | 165553314011363 |
oct | 23401221627323 |
9 | 4663258845008 |
10 | 1340202233555 |
11 | 4774162492a9 |
12 | 1978a702432b |
13 | 994c4036813 |
14 | 48c1a95a9a3 |
15 | 24cdd558155 |
hex | 1380a472ed3 |
1340202233555 has 8 divisors (see below), whose sum is σ = 1647468111744. Its totient is φ = 1046011499200.
The previous prime is 1340202233527. The next prime is 1340202233569. The reversal of 1340202233555 is 5553322020431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1340202233555 - 28 = 1340202233299 is a prime.
It is a super-2 number, since 2×13402022335552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3268785731 + ... + 3268786140.
It is an arithmetic number, because the mean of its divisors is an integer number (205933513968).
Almost surely, 21340202233555 is an apocalyptic number.
1340202233555 is a deficient number, since it is larger than the sum of its proper divisors (307265878189).
1340202233555 is an equidigital number, since it uses as much as digits as its factorization.
1340202233555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6537571917.
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 1340202233555 its reverse (5553322020431), we get a palindrome (6893524253986).
The spelling of 1340202233555 in words is "one trillion, three hundred forty billion, two hundred two million, two hundred thirty-three thousand, five hundred fifty-five".
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