Base | Representation |
---|---|
bin | 11000111101101100… |
… | …01000111111111011 |
3 | 1021121001000000120201 |
4 | 30132312020333323 |
5 | 204422004123003 |
6 | 10053524103031 |
7 | 653060420362 |
oct | 143666107773 |
9 | 37531000521 |
10 | 13402411003 |
11 | 5758347833 |
12 | 2720534a77 |
13 | 1357878817 |
14 | 911d9a7d9 |
15 | 53693eb1d |
hex | 31ed88ffb |
13402411003 has 4 divisors (see below), whose sum is σ = 13407324840. Its totient is φ = 13397497168.
The previous prime is 13402410953. The next prime is 13402411037. The reversal of 13402411003 is 30011420431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13402411003 - 221 = 13400313851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13402411073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2452825 + ... + 2458282.
It is an arithmetic number, because the mean of its divisors is an integer number (3351831210).
Almost surely, 213402411003 is an apocalyptic number.
13402411003 is a deficient number, since it is larger than the sum of its proper divisors (4913837).
13402411003 is an equidigital number, since it uses as much as digits as its factorization.
13402411003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4913836.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 13402411003 its reverse (30011420431), we get a palindrome (43413831434).
The spelling of 13402411003 in words is "thirteen billion, four hundred two million, four hundred eleven thousand, three".
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