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13402413242003 = 371672169026257
BaseRepresentation
bin1100001100000111111000…
…0101001001011010010011
31202110020222020000021221202
43003001332011021122103
53224041120242221003
644300552244541415
72552202202620362
oct303017605113223
952406866007852
1013402413242003
1142a7a27969575
1216055890b186b
13762ac426a7b6
143449748d37d9
15183962d70088
hexc307e149693

13402413242003 has 8 divisors (see below), whose sum is σ = 13847063631072. Its totient is φ = 12962100905856.

The previous prime is 13402413241927. The next prime is 13402413242033. The reversal of 13402413242003 is 30024231420431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13402413242003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13402413242033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1084506950 + ... + 1084519307.

It is an arithmetic number, because the mean of its divisors is an integer number (1730882953884).

Almost surely, 213402413242003 is an apocalyptic number.

13402413242003 is a deficient number, since it is larger than the sum of its proper divisors (444650389069).

13402413242003 is a wasteful number, since it uses less digits than its factorization.

13402413242003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2169026461.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 13402413242003 its reverse (30024231420431), we get a palindrome (43426644662434).

The spelling of 13402413242003 in words is "thirteen trillion, four hundred two billion, four hundred thirteen million, two hundred forty-two thousand, three".

Divisors: 1 37 167 6179 2169026257 80253971509 362227384919 13402413242003