1340300041 has 4 divisors (see below), whose sum is σ = 1340576784. Its totient is φ = 1340023300.

The previous prime is 1340300023. The next prime is 1340300057. The reversal of 1340300041 is 1400030431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1400030431 = 89 ⋅15730679.

It is a cyclic number.

It is not a de Polignac number, because 1340300041 - 2¹⁹ = 1339775753 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340299988 and 1340300024.

It is not an unprimeable number, because it can be changed into a prime (1340300341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130975 + ... + 140836.

It is an arithmetic number, because the mean of its divisors is an integer number (335144196).

Almost surely, 2^1340300041 is an apocalyptic number.

It is an amenable number.

1340300041 is a deficient number, since it is larger than the sum of its proper divisors (276743).

1340300041 is an equidigital number, since it uses as much as digits as its factorization.

1340300041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 276742.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 1340300041 is about 36610.1084538137. The cubic root of 1340300041 is about 1102.5560507151.

Adding to 1340300041 its reverse (1400030431), we get a palindrome (2740330472).

The spelling of 1340300041 in words is "one billion, three hundred forty million, three hundred thousand, forty-one".