13403143425353 has 8 divisors (see below), whose sum is σ = 14622018353856. Its totient is φ = 12184336387600.

The previous prime is 13403143425257. The next prime is 13403143425359. The reversal of 13403143425353 is 35352434130431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13403143425353 - 2¹⁸ = 13403143163209 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13403143425353.

It is not an unprimeable number, because it can be changed into a prime (13403143425359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16559453 + ... + 17349978.

It is an arithmetic number, because the mean of its divisors is an integer number (1827752294232).

Almost surely, 2^{13403143425353} is an apocalyptic number.

It is an amenable number.

13403143425353 is a deficient number, since it is larger than the sum of its proper divisors (1218874928503).

13403143425353 is a wasteful number, since it uses less digits than its factorization.

13403143425353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33945375.

The product of its (nonzero) digits is 777600, while the sum is 41.

Adding to 13403143425353 its reverse (35352434130431), we get a palindrome (48755577555784).

The spelling of 13403143425353 in words is "thirteen trillion, four hundred three billion, one hundred forty-three million, four hundred twenty-five thousand, three hundred fifty-three".