Base | Representation |
---|---|
bin | 111110011010011111… |
… | …1011001010001100011 |
3 | 110210221222202220000001 |
4 | 1330310333121101203 |
5 | 4143444423120003 |
6 | 141323544440431 |
7 | 12453314605111 |
oct | 1746477312143 |
9 | 423858686001 |
10 | 134033020003 |
11 | 51930166813 |
12 | 21b87479117 |
13 | c8405b79bc |
14 | 66b6d76ab1 |
15 | 3746e5c61d |
hex | 1f34fd9463 |
134033020003 has 4 divisors (see below), whose sum is σ = 136230282688. Its totient is φ = 131835757320.
The previous prime is 134033019983. The next prime is 134033020019. The reversal of 134033020003 is 300020330431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134033020003 - 225 = 133999465571 is a prime.
It is a super-2 number, since 2×1340330200032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134033020103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1098631251 + ... + 1098631372.
It is an arithmetic number, because the mean of its divisors is an integer number (34057570672).
Almost surely, 2134033020003 is an apocalyptic number.
134033020003 is a deficient number, since it is larger than the sum of its proper divisors (2197262685).
134033020003 is an equidigital number, since it uses as much as digits as its factorization.
134033020003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2197262684.
The product of its (nonzero) digits is 648, while the sum is 19.
Adding to 134033020003 its reverse (300020330431), we get a palindrome (434053350434).
The spelling of 134033020003 in words is "one hundred thirty-four billion, thirty-three million, twenty thousand, three".
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