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13403403113 = 17974879347
BaseRepresentation
bin11000111101110011…
…11011001101101001
31021121002212102111112
430132321323031221
5204422232344423
610054001240105
7653102022002
oct143671731551
937532772445
1013403403113
115758965161
122720933035
131357b35279
149121781a9
15536a88a78
hex31ee7b369

13403403113 has 4 divisors (see below), whose sum is σ = 13478282640. Its totient is φ = 13328523588.

The previous prime is 13403403067. The next prime is 13403403119. The reversal of 13403403113 is 31130430431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13403403113 - 214 = 13403386729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13403403119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37439495 + ... + 37439852.

It is an arithmetic number, because the mean of its divisors is an integer number (3369570660).

Almost surely, 213403403113 is an apocalyptic number.

It is an amenable number.

13403403113 is a deficient number, since it is larger than the sum of its proper divisors (74879527).

13403403113 is an equidigital number, since it uses as much as digits as its factorization.

13403403113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74879526.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13403403113 its reverse (31130430431), we get a palindrome (44533833544).

The spelling of 13403403113 in words is "thirteen billion, four hundred three million, four hundred three thousand, one hundred thirteen".

Divisors: 1 179 74879347 13403403113