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13403525403155 = 52680705080631
BaseRepresentation
bin1100001100001100000001…
…0111101101001000010011
31202110100211201201221020112
43003003000113231020103
53224100410000400110
644301254454231535
72552241566053616
oct303030027551023
952410751657215
1013403525403155
1142a844872a718
1216058396555ab
13762c407b8914
14344a3c4ba17d
151839ca809405
hexc30c05ed213

13403525403155 has 4 divisors (see below), whose sum is σ = 16084230483792. Its totient is φ = 10722820322520.

The previous prime is 13403525403139. The next prime is 13403525403193. The reversal of 13403525403155 is 55130452530431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13403525403155 - 24 = 13403525403139 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340352540311 + ... + 1340352540320.

It is an arithmetic number, because the mean of its divisors is an integer number (4021057620948).

Almost surely, 213403525403155 is an apocalyptic number.

13403525403155 is a deficient number, since it is larger than the sum of its proper divisors (2680705080637).

13403525403155 is an equidigital number, since it uses as much as digits as its factorization.

13403525403155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2680705080636.

The product of its (nonzero) digits is 540000, while the sum is 41.

Adding to 13403525403155 its reverse (55130452530431), we get a palindrome (68533977933586).

The spelling of 13403525403155 in words is "thirteen trillion, four hundred three billion, five hundred twenty-five million, four hundred three thousand, one hundred fifty-five".

Divisors: 1 5 2680705080631 13403525403155