Base | Representation |
---|---|
bin | 1100001100001100000001… |
… | …0111101101001000010011 |
3 | 1202110100211201201221020112 |
4 | 3003003000113231020103 |
5 | 3224100410000400110 |
6 | 44301254454231535 |
7 | 2552241566053616 |
oct | 303030027551023 |
9 | 52410751657215 |
10 | 13403525403155 |
11 | 42a844872a718 |
12 | 16058396555ab |
13 | 762c407b8914 |
14 | 344a3c4ba17d |
15 | 1839ca809405 |
hex | c30c05ed213 |
13403525403155 has 4 divisors (see below), whose sum is σ = 16084230483792. Its totient is φ = 10722820322520.
The previous prime is 13403525403139. The next prime is 13403525403193. The reversal of 13403525403155 is 55130452530431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13403525403155 - 24 = 13403525403139 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340352540311 + ... + 1340352540320.
It is an arithmetic number, because the mean of its divisors is an integer number (4021057620948).
Almost surely, 213403525403155 is an apocalyptic number.
13403525403155 is a deficient number, since it is larger than the sum of its proper divisors (2680705080637).
13403525403155 is an equidigital number, since it uses as much as digits as its factorization.
13403525403155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2680705080636.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 13403525403155 its reverse (55130452530431), we get a palindrome (68533977933586).
The spelling of 13403525403155 in words is "thirteen trillion, four hundred three billion, five hundred twenty-five million, four hundred three thousand, one hundred fifty-five".
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